Question

A tank of height 5 m is full of water. There is a hole
of cross sectional area 1 cm in its bottom. The initial
volume of water that will come out from this hole
per second is
(1) 10-3 m/s
(2) 104m/s
(3) 10 m/s
(4) 10-2m3/s.​

Answer 1

Velocity of eflux = √(2gh)

Velocity of eflux = √(2gh)v= √(2*5*10) m/s

Velocity of eflux = √(2gh)v= √(2*5*10) m/sv= 10m/s

Velocity of eflux = √(2gh)v= √(2*5*10) m/sv= 10m/sA= 1cm²

Velocity of eflux = √(2gh)v= √(2*5*10) m/sv= 10m/sA= 1cm²A=1*10^-4 m²

Velocity of eflux = √(2gh)v= √(2*5*10) m/sv= 10m/sA= 1cm²A=1*10^-4 m²Volume of that will come out per second =A*v

Velocity of eflux = √(2gh)v= √(2*5*10) m/sv= 10m/sA= 1cm²A=1*10^-4 m²Volume of that will come out per second =A*v= 10*10^-4

Velocity of eflux = √(2gh)v= √(2*5*10) m/sv= 10m/sA= 1cm²A=1*10^-4 m²Volume of that will come out per second =A*v= 10*10^-4=10^-3 m³/s