Question

A tank of oxygen with a pressure of 23 atm is moved from room temperature of 293K to a storage freezer at 239K. What is the final pressure?

Answer 1

Answer:

P1V1 / T1 = P2V2 / T2 ……………… combined gas law

P1 / T1 = P2 / T2 ……………………… Amontons’s law, constant volume

P2 = P1T2 / T1 …………………………. solve for P2

P2 = 23 atm x 239K / 293K

P2 = 19 atm ……………………………… Based on the precision on the pressure, the answer is only expressed to two significant digits.

Explanation:

Given: P1=23 atm; T1=293K; T2=239K; P2=__

Required: P2=__

Equation: Gay-Lussac’s Law; P1*T2=P2*T1; P2= P1*T2/T1

Solution: P2= (23atm) (239K)/293K=18.76atm

Answer: P2=18.76 atm