integration of x/4+x^4
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There is no need to memorise the formula
We will get this integral into the simple form, e^u du
Recall that e^ln4=4
integral 4^x dx=integral (e^ln4)^xdx
set u=ln(4)x
du=ln(4)dx
substitute:
integral e^u(du/ln4)
integral (1/ln4) *e^udu
=(1/ln4) *e^u +C
Substitute back :
(1/ln4)*e^(ln4)x+C
(1/ln4)*(e^ln4)^x +C
= (1/ln4)*4^x+C
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