Question

A tank with dimensions:3m*2m*2m contains water up to its half portion. What is the pressure at the base of the tank? (Density of water=1000kg/m3,g=9.8m/s2)

Answer 1

pressure is force /surface area

P=F/A

so. density is

D=mass per unit volume

D=M/V

do this inorder to get Mass so find volume by saying 3m ×2m×2m

12m^3 is volume

1000=M/12

mass is 12000kg

so find force by saying mass × gravity

12000×9.8

117600N as force

area is L×W so

3×2 = 6m^2 as area

P=F/A

P=117600÷6

pressure is 19600Nm^-1