A tap A can fill a cistern in 8 hours while tap B can fill it in 4 hours. In how much times will the cistern be filled if both A and B are opened together?
Answers
Answer:
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Step-by-step explanation:
Time taken by tap A to fill the cistern = 8 hours.
Work done by tap A in 1 hour = ¹/₈
Time taken by tap B to fill the cistern = 4 hours.
Work done by tap B in 1 hour = ¹/₄
Work done by (A + B) in 1 hour =
(¹/₈ + ¹/₄) = ³/₈
Therefore, time taken by (A + B) to fill the cistern = ⁸/₃ hours = 2 hours 40 min.
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Answer:
Step-by-step explanation:
Given : A tap can fill a cistern in 8 hours and another tap in 10 hours.
To Find:How long will it to fill the tank if both taps are open together.
Solution:
A tap can fill a cistern in 8 hours =1
A tap fill in 1 hours = 1/8
Another tap fill cistern in 10 hours=1
Another tap fill cistern in 1 hour = 1/10
So, together they fill cistern in 1 hour = 1/8+1/10
=9/40
Since they fill 9/40 cistern in 1 hour
They fill 1 cisten in hour =
=40/9
= 4.4 hours
So, it will take 4.4 hours to fill the tank if both taps are open together.
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