Question

determine the nature of the roots of the quadratic equation 2x^2-6x+3=0
please answer it correctly..
wrong answers will be reported​

Answer 1

Step-by-step explanation:

$2 {x}^{2} - 6x + 3 = 0$

$discriminant \: = {b}^{2} - 4ac$

$= ( { - 6)}^{2} - 4 \times 2 \times 3$

$= 36 - 24$

$= 12$

Discriminant > 0

The roots are real and unequal.