Question

A tap can fill an empty tank in 24 minutes. But due to a leakage at the bottom of the tank, it is filled in 36 minutes. If the tank is full, how much time will the leakage take to empty the tank?

(With steps please and no inappropriate answers, Thank you :D)

Answer 1

Step-by-step explanation:

tap can fill in 24 min

due to leakage it takes 36 min

so ,

assuming capacity of tank that is

LCM of 24 and 36 = 72 parts

hence,

normally tap can fill water per min= 72/24=3 parts

due to leakage water fill in tank per min= 72/36= 2 parts

so leakage of water per min is =3-2= 1 part

so, time taken to empty the tank is 72×1= 72 min

Answer 2

Answer:

Given:

A tap can fill a pond in 24 hours, and due to a leakage in the bottom it is filled in 36 hours

Concept:

If a tap can fill a tank in x hours, then the tank filled by the tap in 1 hour = 1/x of the total tank.

Calculation:

Part of pond emptied by leak in an hours =

⇒

Time taken in emptying the full pond = 72 hours

Required time = 72/2 = 36 hours

∴ The required time is 36 hours