Question

A tap is situated 5m above from ground level water drops is falling regular time interval drops are falling in a such way that when first drop toches the ground 3rd drop just leave the tap at that time what is the height of 2nd drop from the tap

Answer 1

Hey friend here is ur solution..

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initial velocity of each drops=0m/s

hence at height of 5 m it takes a time ' t'

Hence ½gt² = 5

or 10*t²=10

or t²=10/10

or t=1

since first drop toches
the ground when 3rd drop just leave

time interval between consecutive
drops = ½sec

hence distance traveled by 2nd drop from tap

=½*10*(½)²

= 10/8

= 1.25 meter from tap...



Hence when third drop just to left

the second drop

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Hope this will help you...