Question

A tap takes 36 hours extra to fill a tank due to a leakage equivalent to half of its inflow. The inflow can fill the tank in how many hours?

Answer 1

leakage is equivalent to half of inflow

ratio of efficiency :- inflow : leakage = 2:1

ratio of time :- inflow : leakage = 1:2

heretime difference (2-1 )= 1 =36 hrs.

time to fill the tank by inflow = 36 hrs




Hope it will help

Answer 2

Inflow can fill the tank in 36 hrs

Step-by-step explanation:

Let say Tap can fill  Tank  in   x  hrs

Tap can fill tank in 1 hrs  = 1/x

leakage equivalent to half of its inflow.

Leakage   in 1 hrs  =  1/2x

Net fill in 1 Hrs  = 1/x - 1/2x    =  1/2x

Tank will be filled with leakage in 1/(1/2x)  = 2x hrs

tap takes 36 hours extra => 2x - x = 36

=> x = 36

inflow can fill the tank in 36 hrs

Learn more:

Two taps can separately fill a tank in 12 min and 15 min. The first tap ...

https://brainly.in/question/9420257

A tap can fill a tank in in 3 hrs the 4 taps of same capacity can fill the ...

https://brainly.in/question/7573575

Two taps A and B can fill a cistern in 6 hours and 9 hours ...

https://brainly.in/question/13433070