a village having a population of 4000 requires 150 l water per head per day it has a tank measuring 20 m buy 15 m buy 6 m from how many days the water of this tank will last
Answers
vol of tank=20*15*6=1800m cube
as 1 m cube contain 1000 litres of water
so water in tank=1800*1000=1800000
now time of water last=amount of water/daily water requirement
i.e.1800000/900000=2
hence water will last for two days.
Answer: 3 days
Step by step explanation:
Given,
Quantity of water in tank = (20 ×15×6) = 1800m³
Population of village = 4000
Water required = 150/per head per day
Quantity of water required by the village per day:
= ( 4000 × 150) liters
= 4000×150 ÷ 1000 m³
= 600 m³
No. of days which the water will last
= 1800÷600
= 3 days
Explanation:
This question can be solved by 2 methods, I have solved this question in very simple way. In this question, There was the Given population and water requires per day.
And, There were a tank, which was wearing of 20 meters, 15 meters and 6 meters. We First find, Quantity of water in tank = (20 ×15×6) = 1800m³.
Then, We find Quantity of water required by the village per day.
= ( 4000 × 150) liters
= 4000×150 ÷ 1000 m³
= 600 m³.
And, Finally we divide it with 600 with 1800. And, we get 3 days.