a tea box measure 12m×9cm×4cm.how many such boxes can be packed in a cardboard box of measure 0.6m×0.45m×0.8m
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Given
length , breadth & height of tea box = 12 m , 9cm , 4cm.
100 cm = 1 m
9cm = 9 /100
4 cm = 4 /100.
volume of tea box = 12×9/100×4/100
= 432 /10000m^3
volume of cardboard box = 0.6×0.45×0.8 m^3
= 0.216 m ^3
no.of box can be packed = volume of cardboard/ volume of tea box.
0.216 / 0.0432 = 5
so 5 boxex can be packed. ans
length , breadth & height of tea box = 12 m , 9cm , 4cm.
100 cm = 1 m
9cm = 9 /100
4 cm = 4 /100.
volume of tea box = 12×9/100×4/100
= 432 /10000m^3
volume of cardboard box = 0.6×0.45×0.8 m^3
= 0.216 m ^3
no.of box can be packed = volume of cardboard/ volume of tea box.
0.216 / 0.0432 = 5
so 5 boxex can be packed. ans
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Answer:
Given
length, breadth and height of a tea box = 12m× 9cm× 4cm
Volume of a tea box = L× B× H
=12m× 0.09m× 0.04m
=0.0432m^3
Volume of cardboard= L× B× H
= 0.6m× 0.04m× 0.8m
= 0.216m^3
Number of such boxes can be packed in cardboard box=0.216m^3 × 10000÷ 0.0432m^3 × 1000
= 5 boxes
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