Question

A teacher in a classroom identified a student suffering with an eye defect and observed his near point at 50cm.
Now answer the following questions.
i.What is his eye defect?
ii.Find the focal length of the lens used to correct his eye defect?​

Answer 1

Explanation:

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Answer 2

ANSWER:

the person need a convex lens to rectify this defect.

EXPLANATION:

calculation of power of lens:

this hypermetropic eye can see the

nearby object kept at 25 CM clearly the images formed at it's own near point i.e.

50 cm

object distance, u=-25cm

image distance, v=-50cm

1/v-1/u=1/f

1/-50 - 1/-25=1/f

f=50 cm

p=100/f = 100/50 = 2D

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