Question

A team of 30 men is supposed to do a work in 38 days ..after 25 days 5 more men were employed and the work was finished one day earlier .how many days would it have been delayed if 5 more men were not employed

Answer 1

1 day late will be the answer

38 - 25 - 1 = 12 days the work was done by 30 + 5= 35 men

let in D days 30 men should have completed the work

therefore

30 * D = 35 * 12
D = 14 days
since after 25 days the remaining days was 38 - 25 = 13 days and as 30 men would have taken 14 days to complete. So they would be late by 1 day ultimately