A team of friends planned to finish a construction work in 60 days. Out of them, 5 friends couldn’t come and the job was finished in 80 days. What was the total number of friends in the starting
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Hi ,
Number friends worked is indirectly
proportion to number of days for
finishing the same work.
Let number of friends worked = x
Number of days to finish the work = y
x y = k ( k is a constant )
According to the given problem ,
x 1 = x ( number of friends started the
work )
y1 = 60 days ,
x2 = ( x - 5 ) ,
y2 = 80 days
x1 × y 1 = x2 × y2
x × 60 = ( x - 5 ) × 80
60x = 80x - 400
60x - 80x = -400
-20x = -400
x = ( -400 )/ ( -20 )
x = 20
Number of friends started the work
= x = 20
I hope this helps you.
Number friends worked is indirectly
proportion to number of days for
finishing the same work.
Let number of friends worked = x
Number of days to finish the work = y
x y = k ( k is a constant )
According to the given problem ,
x 1 = x ( number of friends started the
work )
y1 = 60 days ,
x2 = ( x - 5 ) ,
y2 = 80 days
x1 × y 1 = x2 × y2
x × 60 = ( x - 5 ) × 80
60x = 80x - 400
60x - 80x = -400
-20x = -400
x = ( -400 )/ ( -20 )
x = 20
Number of friends started the work
= x = 20
I hope this helps you.
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