Math, asked by younggriffo, 5 months ago

A team of swimmers is training for a swim meet. The table shows the number of laps each person has swum so far and how long the laps took.

Name Laps Time (minutes)
Jonathan 2 4
Julian 1 1
Seth 3 6
Bennett 7 21
Taylor 4 7

The relationship between time and the number of laps is not proportional across all swimmers. Which two swimmers swam at the same rate (had time and laps in the same proportion)?

Answers

Answered by Fwanzer
14

Answer:

Jonathan and Seth

Step-by-step explanation:

I did the test and got it right.

Answered by GulabLachman
6

Given: A team of swimmers is training for a swim meet. The table shows the number of laps each person has swum so far and how long the laps took.

Name Laps Time (minutes)

Jonathan 2 4

Julian 1 1

Seth 3 6

Bennett 7 21

Taylor 4 7

To find: The two swimmers who swam at the same rate

Solution: For finding the rate of each swimmer, we find the time taken for swimming one lap.

For Jonathan:

Number of laps= 2

Time = 4 minutes

Rate

= Number of laps/ Time

= 2/4

= 0.5 laps / min

For Julian:

Number of laps= 1

Time = 1 minute

Rate

= Number of laps/ Time

= 1/1

= 1 lap / min

For Seth:

Number of laps= 3

Time = 6 minutes

Rate

= Number of laps/ Time

= 3/6

= 0.5 laps / min

For Bennett:

Number of laps= 7

Time = 21 minutes

Rate

= Number of laps/ Time

= 7/21

= 0.33 laps / min

For Taylor:

Number of laps= 4

Time = 7 minutes

Rate

= Number of laps/ Time

= 4/7

= 0.571 laps/ min

Clearly, Jonathan and Seth take 0.5 laps per minute.

Therefore, Jonathan and Seth swam at the same rate.

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