A team won 80 % of the games it played. it played 5 more games of which it won 3 and lst 2. its loss percentage changed to 25%. how many games did it play overall? a)25
b.14
c.16 d)20
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Answered by
29
option D....
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Answer:
Option D is correct.
Step-by-step explanation:
Given:
Percentage of games won = 80%
if 5 more added out of which 3 won and 2 lost.
then percentage of loss = 25%
let x be the total number of games.
According to the question,
Initial loss percentage = 100 - 80 = 20%
Matches lost = 20/100 × x = x/5
Now, games played = x + 5
games lost = x/5+2 = (x+10)/5
So, 25/100 × (x+5) = (x+10)/5
(1/4)(x+5) = (x+10)/5
5(x+5) = 4(x+10)
5x + 25 = 4x + 40
x = 15
Number of games played = 15 + 5 = 20
Therefore, Option D is correct.
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