Math, asked by DevduttNair9126, 1 year ago

A team won 80 % of the games it played. it played 5 more games of which it won 3 and lst 2. its loss percentage changed to 25%. how many games did it play overall? a)25

b.14

c.16 d)20

Answers

Answered by pk473
29
option D....
hope it helps u...
Attachments:
Answered by aquialaska
7

Answer:

Option D is correct.

Step-by-step explanation:

Given:

Percentage of games won = 80%

if 5 more added out of which 3 won and 2 lost.

then percentage of loss = 25%

let x be the total number of games.

According to the question,

Initial loss percentage = 100 - 80 = 20%

Matches lost = 20/100 × x = x/5

Now, games played = x + 5

games lost = x/5+2 = (x+10)/5

So,  25/100 × (x+5) = (x+10)/5

(1/4)(x+5) = (x+10)/5

5(x+5) = 4(x+10)

5x + 25 = 4x + 40

x = 15

Number of games played = 15 + 5 = 20

Therefore, Option D is correct.

Similar questions