A train covers a certain distance at a uniform speed if the train would hae been 6km/hr.faster,it would hae taken 4 hrs less than the scheduled time. and if the train were slower by 6 km/hr it would hae taken 6 hrs more than the scheduled time find the length of the journey
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Let the speed of the train by x km/hr
And the time taken by the train be ‘y’ hrs
Distance traveled by the train is x.y = xy
Case I
If the train would have been 6 km/hr faster, it would have taken 4 hours less than the scheduled time.
⇒ (x + 6) (y - 4) = xy
⇒ -4x + 6y = 24
⇒ 2x – 3y = -12 ---------------- (1)
Case II
If the train were slower by 6 km/hr, it would have taken 6 hours more than the scheduled time
⇒ (x - 6) (y + 6) = xy
⇒ 6x – 6y = 36
⇒ x – y = 12 ----------------(2)
Solve it simultaneously and get the values of x and y.
just solve
And the time taken by the train be ‘y’ hrs
Distance traveled by the train is x.y = xy
Case I
If the train would have been 6 km/hr faster, it would have taken 4 hours less than the scheduled time.
⇒ (x + 6) (y - 4) = xy
⇒ -4x + 6y = 24
⇒ 2x – 3y = -12 ---------------- (1)
Case II
If the train were slower by 6 km/hr, it would have taken 6 hours more than the scheduled time
⇒ (x - 6) (y + 6) = xy
⇒ 6x – 6y = 36
⇒ x – y = 12 ----------------(2)
Solve it simultaneously and get the values of x and y.
just solve
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