Question

A telephone tower stands on atop of the building, a 2 m tall person stand 5 m away from the foot of the building and he observes the top of the tower and foot of the tower at the angle of elevation 60 degrees and 45 degrees find the highest of the building and tower ​

Answer 1

Answer:

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Step-by-step explanation:

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I don't know the answer

Answer 2

Height of building = 7 m

Height of the tower is  = 3.66 m

Step-by-step explanation:

From the diagram,

AB = Length of the tower = y

BD = Length of the building = x + 2

From Δ B C F

$\tan$ 45° = $\frac{x}{5}$

⇒ 1 = $\frac{x}{5}$

⇒ x = 5

Thus height of building = 2 + x = 2 + 5 = 7 m

From Δ A C F

$\tan$ 60° = $\frac{AC}{CF}$

⇒ 1.732 = $\frac{y + x}{5}$

⇒ y + x = 8.66

⇒ y = 8.66 - x

⇒ y = 8.66 - 5

⇒ y = 3.66 m

Thus height of the tower is y = 3.66 m