Chemistry, asked by abhishekkalotranpr, 1 month ago

A temperature of 295 Kalvin is equivalent to approximately

Answers

Answered by ImpressAgreeable4985

0

Answer:

295K − 273.15 = 21.85°C

Explanation:

°F = 9/5 (K - 273) + 32

= 9/5(295 - 273) + 32

= 9/5( 22) + 32

= 39.6 + 32

= 71.6 °F

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