An Organic compound contains 12.8% carbon ,2.1% hydrogen and 85.1% bromine , by mass . its relative molecular mass is 188 .a) calculate empirical formula b) Deduce its molecular formula
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Answer:
Divide the percentages with atomic masses-
carbon
12
12.8
1.06 1
Hydrogen
1
2.1
2.1 2
Bromine
79.9
85.1
1.06 1
Empirical formula- CH
2
Br
(Empirical formula wt)
n
=188 or (94)
n
=188 or n=2
So molecular formula will be - (CH
2
Br)
2
=C
2
H
4
Br
2
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