Question

A tennis ball falls from a height of 4 m
and rises to 3m after bouncing on the
ground. What is the coefficient of
restitution between the ball and the
ground?
O 0.866
O 0.660
O 0.750
O 0.880​

Answer 1

Answer:

Explanation:

0.750

Answer 2

Answer:

Option A- (0.866) is the right choice.

Explanation:

Coefficient of restitution (e) is described as  the ratio of velocity of sepation to velocity of approach of the 2 bodies.

$e=\frac{velocity\ of\ separation}{velocity\ of\ approach}$
Given is a ball which is released from a height of 4m and after bouncing from the ground it bounces to 3m height.

Velocity of the ball just before colliding the ground $(V_{approach})$,$\sqrt{2gh} =\sqrt{2*10*4}=\sqrt{80}m$

Velocity of the ball just after striking the ground $(V_{separation} )$

$\sqrt{2gh} =\sqrt{2*10*3}=\sqrt{60}m$

$e=\frac{velocity\ of\ separation}{velocity\ of\ approach}=\frac{\sqrt{60} }{\sqrt{80} } =\frac{\sqrt{3} }{2}=0.866$

Hence, Coefficient of Restitution between the ball and ground is 0.866.