Question

A tennis ball is thrown up and reaches a
height of 3.2 m. before
coming down.
What was the initial velocity of the ball?
Assume g= 10 m/sq.s​

Answer 1

ans......

A Tennis ball is thrown up and reaches a certain height and comes down in 8s. If value of acceleration due to gravity (g)=10m/s2, then height reached by tennis ball and velocity with  which it strikes the ground respectively is _______ and ______.

A

640m,160m/s

B

320m,120m/s

Your Answer

C

160m,80m/s

D

80m,40m/s

Correct Answer

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CALCULATOR

Enter the know values to find unknown

Acceleration

Distance

Final Velocity

v = u + a*t

Initial Velocity u

m/s

Final Velocity v

m/s

Time t

s

Acceleration a

m/s²

RESET VALUES

ANSWER

Let, ta and tb be the time of ascent and time of descend respectively.

Given, ta+td=8

and ta=td

∴2ta=8

ta=4=td

From first equation of motion, v2=u2+g×td

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