Question

a tennis ball is thrown up and reaches at a height of 6.05m before coming down what is it's initial velocity how much tot time will take to come down (assume g=10m/s)​

Answer 1

Answer:

Initial velocity of the ball is 11 m/s and Time  taken to come down is 1.1 s

Explanation:

height reached by the ball is S= 6.05 m

Final velocity is zero

From the equation of motion

$v^2 = u^2+2gS\\0=u^2+2\times -10 \times 6.05\\u=\sqrt{121} \\u=11 m/s$

Initial velocity of the ball is 11 m/s

Time  taken to come down is

$v =u+at\\11= 10 \times t\\t= 1.1 s$

Time  taken to come down is 1.1 s