Math, asked by dhruvkotian, 7 months ago

A tent in the shape of a cone is made using a canvas whose perpendicular height is 18 m and diameter of the base is 48 m.Find the area of the canvas required to make the conical tent.(Take pi=22/7) *​

Answers

Answered by tennetiraj86
4

Answer:

answer for the given problem is given

Attachments:
Answered by ExᴏᴛɪᴄExᴘʟᴏʀᴇƦ
15

\huge\sf\pink{Answer}

☞ Area of the canvas needed is 2262.85

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\huge\sf\blue{Given}

✭ There is a conical tent made up of canvas

✭ Its height 18 m and diameter is 48 m

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\huge\sf\gray{To \:Find}

◈ The area of the canvas needed?

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\huge\sf\purple{Steps}

\sf \large\underline{\underline{\sf Concept}}

So here we have to find the CSA of the cone, this is because here we are asked the area of the canvas and not the area of the whole tent, as we won't cover the bottom part CSA would give us our Answer!!

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CSA of a cone is given by,

\underline{\boxed{\sf CSA_{Cone} = \pi rl}}

First we shall find the radius,

»» \sf Radius = \dfrac{Diameter}{2}

»» \sf Radius = \dfrac{48}{2}

»» \sf \green{Radius = 24 \ m}

Now the Slant height of the cone,

\sf L = \sqrt{r^2+h^2}

\sf L = \sqrt{24^2+18^2}

\sf L = \sqrt{576+324}

\sf L = \sqrt{900}

\sf \red{Length = 30 \ m}

Substituting these values in the formula to find CSA of cone,

\sf CSA_{Cone} = \pi rl

\sf CSA = \dfrac{22}{7} \times 24\times 30

\sf \orange{CSA = 2262.85 \ m^2}

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