A tent is in shape of right circular cylinder up to a height of 3m and a cone above it. The maximum height of tent above ground is 13.5m. Calculate the cost of painting the inner side of tent at rate of Rs. 3/sq m if radius of base is 14m.
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Answer:
Radius of base of cylindrical portion=14m
Height of cylindrical portion=3m
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Curved surface area of cylindrical part=2× -------- × 14 × 3
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Height of conical part=13.5−3=10.5m
For conical part:r=14m,h=10.5m
_________
l = √(14)² +(10.5) ² = 306.25
l = 17.5m
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CSA of conical part= πrl = -------- × 14 × 17.5=770m²
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∴Total area to be painted = (264+770)m² = 1034m²
Cost of painting = Rs. (1034×2) = Rs. 2068
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