A tent is in the form of a right circular cylinder surmounted by a cone. the diameter of the cylinder is 24 m. the height of the cylindrical portion is 11 m, while the vertex of the cone is 16 m above the ground. what is the area of the curved surface for conical portion?
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C.S.A of cone = pie x r x l ( l = slant height of the cone)
Height of cone = 5 m
Slant height = root of the square of height + square of radius
So , l = 13 m ( root of 25 + 144 = 13 )
Now putting the values in the formula ,
22/7*12*13= 490.28 m
(Plz note that the answer is only up to two decimal place )
Height of cone = 5 m
Slant height = root of the square of height + square of radius
So , l = 13 m ( root of 25 + 144 = 13 )
Now putting the values in the formula ,
22/7*12*13= 490.28 m
(Plz note that the answer is only up to two decimal place )
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