Question

A tent is in the form of a right circular cylinder is surrounded by a cone the diameter of a cylinder is 24 m and height of the cylinder portion is 11 meter while the vertex of a cone and 16m above the ground find the area of the canvas required for the tent

Answer 1

CSA of cylinder=2*pi*r*h
=2×22/7×24/2×11
=829.71 m^2
Then,
slant height=root r^2+h^2
=root 12^2+(16-11)^2
=root 144 + 25
Hence, slant height=13 m
Now,
CSA of cone=pi*r*l
=22/7×12×13
=490.28 m^2
Then,
Total area of canvas required for tent
=829.71+490.28
=1319.99 m^2
Hope it helps u.

Answer 2

"Total “area of canvas” required for tent is $1319.99\quad { m }^{ 2 }$.

Given:

D = 24 m

Height of the cylinder = 11 m

Total height from the ground = 16 m

To find:

Area of the canvas required for tent

Solution:

Curved Surface Area of a cylinder $= 2\quad \times \quad \pi \quad \times \quad r\quad \times \quad h$

$=\quad 2\quad \times \quad \frac { 22 }{ 7 } \quad \times \quad \frac { 24 }{ 2 } \quad \times \quad 11\quad =\quad 829.71\quad { m }^{ 2 }$

Then,

$Slant\quad height\quad \quad l\quad =\quad \sqrt { { r }^{ 2 }+{ h }^{ 2 } } \quad =\sqrt { { 12 }^{ 2 }+{ (16-11) }^{ 2 } }$

$= \sqrt { 144+ 25 }$

Hence, slant height l = 13 m

Now,

$CSA of cone =\quad \pi \quad \times \quad r\quad \times \quad l$

$=\quad \frac { 22 }{ 7 } \quad \times \quad 12\quad \times \quad 13\quad$

$=\quad 490.28\quad { m }^{ 2 }$

Then,

Total area of canvas required for tent

= 829.71 + 490.28

$= 1319.99\quad { m }^{ 2 }.$"