a tent is in the shape of a cylinder surmounted by a conical top of height 2.1 m and base radius 2m................. can we include base area of cylinder while calculating surface area
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Given:
Height (h) of the cylindrical part = 2.1 m
Diameter of the cylindrical part = 4 m
Radius of the cylindrical part = 2 m
Slant height (l) of conical part = 2.8 m
Area of canvas used = CSA of conical part + CSA of cylindrical part
=πrl+2πrh
=π×2×2.8+2π×2×2.1
=2π[2.8+4.2]
=2×
7
22
×7
=44m
2
Cost of 1 m
2
canvas =500 rupees
Cost of 44 m
2
canvas =44×500=22000 rupees.
Therefore, it will cost 22000 rupees for making such a tent.
HOPE IT’S HELP YOU
Height (h) of the cylindrical part = 2.1 m
Diameter of the cylindrical part = 4 m
Radius of the cylindrical part = 2 m
Slant height (l) of conical part = 2.8 m
Area of canvas used = CSA of conical part + CSA of cylindrical part
=πrl+2πrh
=π×2×2.8+2π×2×2.1
=2π[2.8+4.2]
=2×
7
22
×7
=44m
2
Cost of 1 m
2
canvas =500 rupees
Cost of 44 m
2
canvas =44×500=22000 rupees.
Therefore, it will cost 22000 rupees for making such a tent.
HOPE IT’S HELP YOU
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