Math, asked by pradhanjyoti220, 5 months ago

a tent is in the shape of a cylinder surmounted by a conical top of same diameter if the height and diameter of cylindrical part are 2.1m and 3m respectively and the slant height of conical part is 2.8m find the cost of canvas needed to make the tent of the canvas is needed to make the tent if the canvas is available at the rate of 500 sq./meter​

Answers

Answered by guptaankita5252
1

Answer:

Radius of the conical part = radius of cylindrical part r=

2

3

m

Slant height of the cone l=2.8 m

Height of the cylinder, h=2.1 m

Canvas needed to make the tent = Curved surface area of the conical part + curved surface area of the cylindrical part.

Curved surface area of conical part = πrl=

7

22

×

2

3

×2.8=13.2

Curved surface area of cylindrical part =2πrh=2×

7

22

×

2

3

×2.1=19.8

Total surface area = Curved surface area of conical part + Curved surface area of cylindrical part

=13.2+19.8=33 m

2

Cost of 1 m

2

canvas = Rs. 500

Cost of 33 m

2

canvas =33×500=16500

Therefore, it will cost Rs. 16500 for making such a tent.

Answered by harivatsshakya
0

Answer:

radius of the Canonical part is equal to radius of cylinder Kal are is equals to

2

e

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