Question

a tent is in the shape of a cylinder surmounted by a conical top of same diameter. If the height and the diameter of a cylindrical part are 2.1 m and 3m and slant height of conical part is 2.8 m .find the cost of Canvas needed to make the tent if the Canvas is available at the rate of ₹ 500 per square metre. Also find the volume of air enclosed in the tent

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Answer 1

Answer:

Step-by-step explanation:

In the figure, a tent is in the shape of a cylinder surmounted by a conical top of same diameter.

ANSWER

Radius of the conical part = radius of cylindrical part r=

2

3

​

m

Slant height of the cone l=2.8 m

Height of the cylinder, h=2.1 m

Canvas needed to make the tent = Curved surface area of the conical part + curved surface area of the cylindrical part.

Curved surface area of conical part = πrl=

7

22

​

×

2

3

​

×2.8=13.2

Curved surface area of cylindrical part =2πrh=2×

7

22

​

×

2

3

​

×2.1=19.8

Total surface area = Curved surface area of conical part + Curved surface area of cylindrical part

=13.2+19.8=33 m

2

Cost of 1 m

2

canvas = Rs. 500

Cost of 33 m

2

canvas =33×500=16500

Therefore, it will cost Rs. 16500 for making such a tent.

Answer 2

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