Question

A tent is in the shape of a cylinder surmounted by a conical top. If the height and diameter of the cylindrical part are 2.5 m and 4 m respectively, and the slant height of the top is 2.8 m, find the area of the canvas used for making the tent. Also, find the cost of the canvas of the tent at the rate of Rs 600 per m².

ik the answer cz this question is from previous grade but you guys need to solve everything. kk???

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Answer 1

Answer:

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Answer 2

${\large{\underline{\underline{\pmb{\frak{Given:-}}}}}}$

★ A tent is in the shape of a cylinder surmounted by a conical top.

★ The height of the cylindrical part is 2.5 m.

★ Diameter of the cylindrical part is 4 m.

★ Slant height of the top is 2.8 m.

★ The cost of the rate of the canvas can be find out at the rate of Rs. 600 per m².

${\large{\underline{\underline{\pmb{\frak{To\ find:-}}}}}}$

★ The cost of the canvas of the tent at the rate of Rs 600 per m².

${\large{\underline{\underline{\pmb{\frak{Using\ concepts:-}}}}}}$

★ Formula to find the radius of the cylindrical part.

★ Formula to find the CSA of cylinder.

★ Formula to find the CSA of top.

★ Formula to find total area.

★ Formula to find total cost.

${\large{\underline{\underline{\pmb{\frak{Using\ formulas:-}}}}}}$

★ Radius = Diameter/2.

★ CSA of cylinder = 2πrh.

★ CSA of top = πrl.

★ Total area = CSA of cylindrical part + CSA of top.

★ Total cost = Total area of canvas × Given rate.

${\large{\underline{\underline{\pmb{\frak{Solution:-}}}}}}$

★ Total area of the canvas used for making the tent is 49 m².

★ Total cost of the canvas of the tent at the rate of Rs. 600 per m² is Rs. 29400.

${\large{\underline{\underline{\pmb{\frak{Diagrams:-}}}}}}$

The slant height is given. Hence, it is at the slant part nor in the middle part.

${\large{\underline{\underline{\pmb{\frak{Full\ solution:-}}}}}}$

➟ Radius = Diameter/2

➟ Radius = 4/2

➟ Radius=2

_

➟ CSA of cylinder = 2πrh

➟ CSA of cylinder = 2 × 3.14 × 2 × 2.5

➟ CSA of cylinder = 2 × 6.28 × 2.5

➟ CSA of cylinder = 2 × 15.7

➟ CSA of cylinder = 31.4 m².

_

➟ CSA of the top = πrl

➟ CSA of the top = 3.14 × 2 × 2.8

➟ CSA of the top = 6.28 × 2.8

➟ CSA of the top = 17.6 m².

_

➟ Total area = CSA of cylindrical part + CSA of the top

➟ Total area = 31.4 + 17.6

➟ Total area = 49 m².

_

➟ Total area = CSA of cylindrical part + CSA of the top

➟ Total area = 31.4 + 17.6

➟ Total area = 49 m².

_

➟ Total cost = Total area of the canvas × Given rate

➟ Total cost = 49 × 600

➟ Total cost = Rs. 29400.