Question

write a quadratic polynomial whose zeroes are 8 and 1/3 (Explain)

Answer 1

Answer:

8+1/3=25/3

8*1/3=8/3;

then the eq = $x^{2} - \frac{25}{3}x + \frac{8}{3}$

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

sum of zeros = 8 + $\frac{1}{3}$

                       $=\frac{24 + 1}{3}$

                       $=\frac{25}{3}$

product of zeros = $8 \times \frac{1}{3}$

                           $= \frac{8}{3}$

thus the required equation is,

x²- (sum of the roots) x + product of the roots = 0

$x^{2} -(\frac{25}{3})x+\frac{8}{3}=0$

$\frac{3x^{2} -25x+8}{3} =0$

$3x^{2} -25x+8=0$