A tent is in the shape of triangular prism resting on rectangular base if ab =AC, ad=.8
Answers
Thank you for asking this question. Here is your answer:
∠ACB = ∠ABC (AB = AC)
∠ACB = 42°
sin∠ACB = AD/AB
Sin 42° = 0.8/AB
AB = 0.8/ Sin 42°
= 1.2m
So the volume of tent = area of ΔABC x length of tent
= 1/2 x AD x BC x Length of Tent
Length of Tent = 6m
BC = 3m
AD = 0.8m
Volume of tent = 1/2 x 0.8 x 3 x 6
= 0.4 x 18
= 7.2 m³
If there is any confusion please leave a comment below.
Answer:Thank you for asking this question. Here is your answer:∠ACB = ∠ABC (AB = AC)∠ACB = 42°sin∠ACB = AD/ABSin 42° = 0.8/ABAB = 0.8/ Sin 42°= 1.2mSo the volume of tent = area of ΔABC x length of tent= 1/2 x AD x BC x Length of TentLength of Tent = 6mBC = 3mAD = 0.8mVolume of tent = 1/2 x 0.8 x 3 x 6= 0.4 x 18= 7.2 m³
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