A tent is of shape of right circular cylinder upto height of 3m and then becomes a right circular cone with a maximum height of 13.5 m above ground. Calculate the cost of painting inner side pf tent at the rate of Rs20 per sq metre if the radius of base is 14m
Answers
Answer:
CSA of cylinder =2πrh
\begin{lgathered}2 \times \frac{22}{7} \times 14 \times 3 \\ = 264 {m}^{2}\end{lgathered}
2×
7
22
×14×3
=264m
2
radius=14m
height =13.5-3=10.5
l {}^{2} = r {}^{2} + h {}^{2}l
2
=r
2
+h
2
\begin{lgathered}14 { }^{2} + 10.5 { }^{2} \\ 196 + 110.25 \\ = 306.25 \\ l \sqrt{306.25 } \\ l = 17.5m\end{lgathered}
14
2
+10.5
2
196+110.25
=306.25
l
306.25
l=17.5m
CSA of cone =πrl
\begin{lgathered}\frac{22}{7} \times 14 \times 17.5 \\ = 770 {m}^{2}\end{lgathered}
7
22
×14×17.5
=770m
2
total area=264+770
1034 {m}^{2}1034m
2
cost of cloth per square m = Rs80
cost of cloth
1034 {m}^{2}1034m
2
\begin{lgathered}80 \times 1034 \\ = 82720\end{lgathered}
80×1034
=82720
Answer: Rs 2068
Step-by-step explanation:
CSA of Tent = CSA of cylinder + CSA of cone
= 2rh + rl
= 2 (14) (3) + (14)
= 264 + 14
=264 + 14 (17.5)
= 264 + 770
= 1034 m2.
Cost of painting the inside of tent, i.e., 1034 m2 at the rate of Rs. 2 per sq m = Rs 1034 x 2 = Rs. 2068.