Question

A tent is of the shape of a right circular cylinder upto a height of 3 metres and then becomes a right circular cone with a maximum height of 13.5 metres above the ground. Calculate the cost of painting the inner side of the tent at the rate of Rs 2 per square metre, if the radius of the base is 14 metres.

Answer 1

Answer:

The Cost of painting the inner side of the tent is ₹ 2068 .

Step-by-step explanation:

SOLUTION :

Given :

Radius of the cylinder and cone, r = 14 cm

Height of a cylinder, h = 3 m

Total height of the tent = 13.5 m

Height of the conical part, H = 13.5 - 3 = 10.5 m

Slant height of the cone, l = √r² + H²

l = √14² + 10.5²

l = √196 + 110.25

l = √306.26

l = 17.5 m

Slant height of the cone, l = 17.5 m

Area of inner side of the tent = curved surface area of cone + curved surface area of the cylinder

= πrl + 2πrh

= πr(l + 2h)

= π× 14(17.5 + 2 × 3)

= 14π (17.5 + 6)

= 14π (23.5)

= 14 × 22/7 × 23.5

= 44 × 23.5  

= 1034 m²

Area of inner side of the tent = 1034 m²

Rate of painting the inner side of the tent = ₹ 2 per m²

Cost of painting the inner side of the tent = 1034 × 2 = ₹ 2068  

Hence, the Cost of painting the inner side of the tent is ₹ 2068 .

HOPE THIS ANSWER WILL HELP YOU….

Answer 2

Step-by-step explanation:

hope it help thank you so much