prove that n^2-n is divisuble by 2 for every integer n
mkrishnan:
i know very easy proof
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Step-by-step explanation:
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thank u so much
anytime
Answered by
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Answer:Step-by-step explanation:
n^2-n = n[n-1]
if n is even n[n-1] is even
if n is odd n-1 is even so n[n-1] is even
so n^2-n is divisible by 2 for every integer n
thanks
this is the best way to prove
u r briliant
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