Question

prove that n^2-n is divisuble by 2 for every integer n

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:Step-by-step explanation:

n^2-n =  n[n-1]

 if n is even  n[n-1] is even  

if n is odd  n-1 is even   so n[n-1] is even

so  n^2-n is divisible by 2 for every integer n