Math, asked by Anonymous, 1 year ago

prove that n^2-n is divisuble by 2 for every integer n

mkrishnan: i know very easy proof

Answers

Answered by brunoconti

1

Answer:

Step-by-step explanation:

Attachments:

Anonymous: thank u so much

brunoconti: anytime

Answered by mkrishnan

1

Answer:Step-by-step explanation:

n^2-n = n[n-1]

if n is even n[n-1] is even

if n is odd n-1 is even so n[n-1] is even

so n^2-n is divisible by 2 for every integer n

Anonymous: thanks

mkrishnan: this is the best way to prove

Anonymous: u r briliant

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