Math, asked by umeshyadav04282, 1 month ago

A tent is of the shape of right circular cylinder upto a height of 3m and then became a right circular cone with a maximum height of 13.5 m above the ground. calculate the coast of painting the inner side of the tent at the rate of rupees 2per m square, if the radius of the base is 14m​

Answers

Answered by manishkasyabguptmrm
2

Answer:

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Answered by ashauthiras
2

Answer:

The Cost of painting the inner side of the tent is ₹ 2068

Step-by-step explanation:

Radius of the cylinder and cone, r = 14 cm

Height of a cylinder, h = 3 m

Total height of the tent = 13.5 m

Height of the conical part, H = 13.5 - 3 = 10.5 m  

Slant height of the cone, l = √r² + H²

l = √14² + 10.5²

l = √196 + 110.25

l = √306.26

l = 17.5 m

Slant height of the cone, l = 17.5 m

Area of inner side of the tent = curved surface area of cone + curved surface area of the cylinder

= πrl + 2πrh

= πr(l + 2h)

= π× 14(17.5 + 2 × 3)

= 14π (17.5 + 6)

= 14π (23.5)

= 14 × 22/7 × 23.5

= 44 × 23.5  

= 1034 m²

Area of inner side of the tent = 1034 m²

Rate of painting the inner side of the tent = ₹ 2 per m²

Cost of painting the inner side of the tent = 1034 × 2 = ₹ 2068  

Hence, the Cost of painting the inner side of the tent is ₹ 2068

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