Question

A tent is to be built in the form of a cylinder of radius 10 m surmounted by a cone of the same radius. if the height of the cylindrical part is 5 m and slant height of the conical part is 15 m, how much canvas will be required to build the tent? allow 20% extra canvas for folding and stitching. (take π = 22/7)

Answer 1

canvas required to build the tent = 660/7 sq. m

Answer 2

Answer:

$785.713m^2$

Step-by-step explanation:

Height of Cylinder = 5 m

Radius of Cylinder = 10 m

So, Lateral surface area of cylinder = $2\pi rh$

                                                         = $2 \times \frac{22}{7} \times 10 \times 5$

                                                         = $314.285m^2$

Slant height of cone(l) = 15 m

Radius of cone = 10 m

So, Lateral surface area of cone = $\pi r l$

                                                      = $\frac{22}{7} \times 10 \times 15$

                                                      = $471.428 m^2$

So, the total canvas is required to build the tent = $314.285+471.428$

                                                                                = $785.713m^2$

Hence ,the total canvas is required to build the tent is $785.713m^2$