A tent of height 8.25 m os formed by surmounting a cone of same based on a cylinder with diameter of base 30 m and height 5.5 m. Find the cost of the canvas of the tent at the rate of ₹45 per m². Plz solve urgently.
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Answer:
total height = 8.25m
cylinder
h=5.5m
r=15m
CSA= πrl+2πrh
( l^2=h^2 + r^2
. = (2.75)^2+(15)^2
=7.56 + 225
= 232.56
l = 15.24)
CSA = π(rl+2rh)
= 22/7(15X15.24+2X15X5.5)
=22/7X15(15.24+11)
= 22/7X15(26.24)
= 22/7X15X26.24
= 8659.2/7
= 1237.02
cost of canvas = 1327.02X45
=55665.9 rupees
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