Question

A tent of height 8.25 m os formed by surmounting a cone of same based on a cylinder with diameter of base 30 m and height 5.5 m. Find the cost of the canvas of the tent at the rate of ₹45 per m². Plz solve urgently. ​

Answer 1

Answer:

total height = 8.25m

cylinder

h=5.5m

r=15m

CSA= πrl+2πrh

( l^2=h^2 + r^2

. = (2.75)^2+(15)^2

=7.56 + 225

= 232.56

l = 15.24)

CSA = π(rl+2rh)

= 22/7(15X15.24+2X15X5.5)

=22/7X15(15.24+11)

= 22/7X15(26.24)

= 22/7X15X26.24

= 8659.2/7

= 1237.02

cost of canvas = 1327.02X45

=55665.9 rupees