Question

a test charge 1.6 *10`19 cb is moving with velocity v= (2i+3j) m/sec is a magnetic field B = (2i+3j)wb /m2 .the magnetic force on the test charge

Answer 1

magnetic force on the test charge is zero.

given, charge , q = 1.6 × 10^-19 C

velocity, v = (2i + 3 j) m/s

magnetic field, B = (2i + 3j) wb/m²

magnetic force is given by, F = q (v × B)

= 1.6 × 10^-19 [(2i + 3j) × (2i + 3j) ]

[ velocity and magnetic field both are in same direction. even their magnitudes are also same. so, angle between velocity and magnetic is 0° ]

= 1.6 × 10^-19 [|2i + 3j|²sin0° ]

= 0

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