Question

a test tube loaded with lead shots weights 50gf and floats uoto the mark x in water the test tube is made to float alcohol it is found 20 gf of leads shot have to be removed so as to float it to level x find rd of alcohol

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Answer 1

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Answer 2

Explanation:

Given A test tube loaded with lead shots weights 50gf and floats up to the mark x in water the test tube is made to float alcohol it is found 20 gf of leads shot have to be removed so as to float it to level x find rd of alcohol

• Let m1 be the weight of the water displaced and m2 be the weight of alcohol displaced.
• According to the question
• When test tube floats on water its weight will be 50 gf
• So by Archimedes principle weight of water displaced is equal to weight of test tube.
• Now test tube floats on alcohol we have  
• 20 gf lead shots have to be removed to float up to the level x.
• Therefore weight of test tube in alcohol will be 50 gf – 20 gf
•                                                                                      = 30 gf
• So the relative density of alcohol will be weight of alcohol displaced / weight of the water displaced.
•                                                                         = 30 / 50
•                                                                        = 3/5
•                                                                         = 0.6

Reference link will be

https://brainly.in/question/3686601