Math, asked by Deepeshyadav9315, 7 months ago

A=\left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \\

Answers

Answered by aryan073
0

Answer::

(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)(⌒o⌒)

\underline{\underline{{\purple{\sf Given}}}}

A=\left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]\\

\longrightarrow\small\boxed{\tt\red \:By\:determinant \: form}

\longrightarrow\small\boxed{\sf\pink{1(5\times9-6\times8)-2(4\times9-6\times7)+3(4\times8-5\times7}}

\implies\sf\pink{1(45-48)-2(36-42)+3(32-35)}

\implies\sf\pink{1(-3)-2(-6)+3(-3)}

\implies\sf\pink{-3+12-9}

\implies\sf\pink{-12+12}{\red=0}

\bigstar\small\boxed{\tt\blue{A=0}}

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