Question

a the following examples. a. If the speed of light in a medium is 1.5 x 10 m/s, what is the absolute refractive index of the medium? ​

Answer 1

EXPLANATION.

Speed of light in a medium = 1.5 x 10⁸ m/s.

As we know that,

Absolute refractive index of medium = speed of light in vacuum/speed of light in medium.

⇒ n = c/v.

⇒ c = 3 x 10⁸ m/s.

⇒ v = 1.5 x 10⁸ m/s.

⇒ n = (3 x 10⁸)/(1.5 x 10⁸).

⇒ n = (3 x 10)/(15) = 30/15.

⇒ n = 2.

                                                                                                                   

MORE INFORMATION.

(1) Mirror formula

⇒ 1/f = 1/v + 1/u.

(2) Lens formula.

⇒ 1/f = 1/v - 1/u.

(3) Snell's law.

⇒ sin(i)/sin(r) = n.

(4) Magnification produced by mirror.

⇒ m = h'/h = -v/u.

(5) Magnification produced by lens.

⇒ m = h'/h = v/u.

(6) Power of lens.

⇒ p = 1/f.

Answer 2

Answer:

Appropriate Question :-

• If the speed of light in a medium is 1.5 × 10⁸ m/s, what is the absolute refractive index of the medium ?

Given :

• The speed of light in a medium is 1.5 × 10⁸ m/s.

To Find :-

• What is the refractive index of the medium.

Formula Used :-

$\clubsuit$ Medium Index of the refraction Formula :

$\bigstar \: \: \sf\boxed{\bold{\pink{n =\: \dfrac{c}{v}}}}\: \: \: \bigstar$

where,

• n = Medium Index of the refraction
• c = Speed of light in a vacuum (3 × 10⁸ m/s)
• v = Speed of light in the medium

Solution :-

Given :

• Speed of light in a vacuum (c) = 3 × 10⁸ m/s
• Speed of light in the medium (v) = 1.5 × 10⁸ m/s

According to the question by using the formula we get,

$\implies \sf\bold{\purple{n =\: \dfrac{c}{v}}}$

$\footnotesize \implies \bf n =\: \dfrac{Speed\: of\: light\: in\: vacuum}{Speed\: of\: light\: in\: medium}$

$\implies \sf n =\: \dfrac{3 × \cancel{10^8}}{1.5 \times \cancel{10^8}}$

$\implies \sf n =\: \dfrac{3 \times 1}{1.5 \times 1}$

$\implies \sf n =\: \dfrac{3}{1.5}$

$\implies \sf\bold{\red{n =\: 2}}$

$\therefore$ The medium index of refraction is 2 .