Question

a) The mass of lead is 232g and its volume is 20cm3. Find the density of lead in kg/m3​

Answer 1

Answer:

11600 kg/m³

Explanation:

As per the provided information in the given question, we have :

• Mass of lead = 232 g
• Volume of lead = 20 cm³

We are asked to calculate the density of lead in kg/m³.

In order to calculate the density of lead in kg/m³, we need to convert mass of lead in kilograms and volume of lead in m³.

Converting mass in kg :

$\longmapsto \rm { 1 \; g = \dfrac{1}{1000} \; kg}$

$\longmapsto \rm { 232 \; g = \dfrac{232}{1000} \; kg}$

$\longmapsto \bf {232 \; g = 0.232 \; kg}$

Converting volume in m³ :

$\longmapsto \rm { 1 \; cm^3 = \dfrac{1}{1000000} \; m^3}$

$\longmapsto \rm { 20 \; cm^3 = \dfrac{20}{1000000} \; m^3}$

$\longmapsto \rm { 20 \; cm^3 = \dfrac{2}{100000} \; m^3}$

$\longmapsto \bf { 20 \; cm^3 = 0.00002 \; m^3}$

Calculating the density of lead in kg/m³ :

$\longmapsto \bf {Density = \dfrac{Mass}{Volume} }$

Substituting the values, we get :

$\longmapsto \rm {Density = \dfrac{0.232 \; kg}{0.00002 \; m^3 } }$

$\longmapsto \rm {Density = \dfrac{232 \times 100000 \; kg}{2 \times 1000 \; m^3 } }$

$\longmapsto \rm {Density = \dfrac{232 \times 100 \; kg}{2 \; m^3 } }$

$\longmapsto \rm {Density = \dfrac{23200 \; kg}{2 \; m^3 } }$

$\longmapsto \bf {Density = 11600 \; kg.m^{-3}}$

∴ Density of the lead is 11600 kg/m³.