Question

A the P.E =2.4 J and K.E. = 0J, at B the K.E. is 2.0 J and at C the P.E is 0J. Calculate (i) The P.E. at B (ii) The K.E. at C (iii) The K.E. and P.E. at D​

Answer 1

Answer:

In an SHM, variation of potential energy with displacement d is given by

P.E.(y)=

21 kd 2

, which represents the equation of a straight parabola with vertex at d=0.

And variation of kinetic energy with displacement d is given by

K.E.(y)= 21

k(a 2 −d 2), which represents the equation of an inverted parabola with vertex at d=a.

Here a is the amplitude of the SHM.

Explanation:

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