(a) The probability that a vehicle entering the Luray Caverns has Canadian
license plates is 0.12, the probability that it is a camper is 0.28; and the
probability that it is a camper with Canadian license plates is 0.09. What is
the probability that
1) A camper entering the Luray Caverns has Canadian license Plates.
(1) A vehicle with Canadian license plates entering the Luray Caverns is a
camper.
(ii) A vehicle entering the Luray Caverns does not have Canadian plates or
is not a camper.
Answers
p(Canadian license plates)= 0.12
p(camper)= 0.28
p( camper with Canadian license plates)= 0.09
(a) P(camper with Canadian license plates) = .12
(b) P(a vehicle with Canadian license plates is a camper)
P(A|B) = P(A and B)/P(B)
P(Camper| Canadian Plates) = .09/.12 = .75
(c) P( vehicle A:does not have Canadian plates 0r B: is not a camper)
P(A 0r B) = P(A) + P(B) - P(A and B) = .88 + .72 - .81 = .80
Given : The probability that a vehicle entering the Luray Caverns has Canadian license plates is 0.12,
the probability that it is a camper is 0.28;
probability that it is a camper with Canadian license plates is 0.09.
To Find : What is the probability that
1) A camper entering the Luray Caverns has Canadian license Plates.
(2) A vehicle with Canadian license plates entering the Luray Caverns is a
camper.
(3) A vehicle entering the Luray Caverns does not have Canadian plates or
is not a camper.
Solution:
probability that
1) A camper entering the Luray Caverns has Canadian license Plates.
= 0.12,
probability that
(3) A vehicle with Canadian license plates entering the Luray Caverns is a
camper.
= camper with Canadian license plates / Canadian license plates
= 0.09/ 0.12
= 9/12
= 3/4
= 0.75
probability that
A vehicle entering the Luray Caverns does not have Canadian plates or
is not a camper. 1 - P ( Canadian plates or camper)
P ( Canadian plates or camper) = 0.12 + 0.28 - 0.09 = 0.31
A vehicle entering the Luray Caverns does not have Canadian plates or
is not a camper. 1 - P ( Canadian plates or camper)
= 1 - 0.31
= 0.69
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