Question

a)The sum of two numbers is 40. Taking the numbers as x and y from an equation b)Their difference is 10 . Using this idea from another equation c)Find the numbers​

Answer 1

Step-by-step explanation:

CHECK your answer

Answer 2

Given: The Sum of two numbers is 40. & The difference of these two numbers is 10.

Need to find: The numbers?

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❍ Let's say, that the numbers are x and y respectively.

Given that,

• Difference of these two numbers is 10.

$:\implies\sf x - y = 10\qquad\qquad\quad\quad\sf\Bigg\lgroup eq^{n}\;(1)\Bigg\rgroup$

• Sum of these two numbers is 40.

$:\implies\sf x + y = 40\qquad\qquad\quad\quad\sf\Bigg\lgroup eq^{n}\;(2)\Bigg\rgroup$

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⌑ From eqₙ ( I ) & eqₙ ( II ) :

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$\dashrightarrow\sf x + \;\cancel{\;y}\; + x -\;\cancel{\; y}\; = 40 + 10$

$\dashrightarrow\sf 2x = 50$

$\dashrightarrow\sf x = \cancel\dfrac{50}{2}$

$\dashrightarrow{\pmb{\underline{\boxed{\frak{\red{x = 25}}}}}}\;\bigstar$

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✇ Putting Value of 'x' in eqₙ ( II ) :

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$\dashrightarrow\sf x + y = 40$

$\dashrightarrow\sf 25 + y = 40$

$\dashrightarrow\sf y = 40 - 25$

$\dashrightarrow{\pmb{\underline{\boxed{\frak{\red{y = 15}}}}}}\;\bigstar$

$\therefore{\underline{\textsf{Hence, the numbers are \textbf{25} and \textbf{15} respectively.}}}$ ⠀⠀