A theft is reported to a policeman. The thief starts running and the policeman chases him. When the policeman starts chasing, the thief was at a distance of 250 metre. The thief and the policeman run at the speed of 8 km/h and 9 km/h respectively. Find the time the policeman will take to catch the thief.
Answers
Answer:
15 min
distance = speed× time(1)
difference of speed = 9-8 = 1 km/ hr
ie, 1 km/ hr =250 m
1 km/hr = 250/1000 km
1 km/ hr = 1/4 km
substitute in (1)
1/4 = 1 × time
time = 1 /4 × 60
= 15 min
The time taken by the policeman to catch the thief is 15 mins
Given,
the initial distance between the thief and the policeman = 250 m = 1/4 km
speed of thief = 8 km/h =
speed of policeman = 9 km/h
To Find,
Time taken for the policeman to reach the thief
Solution,
The given problem can be solved using a simple method
We know that distance = speed x time
When the thief and the policemen meet, the distance traveled by the policeman would be 1/4 m longer than the distance traveled by the thief
⇒ distance traveled by policeman = 1/4 m + distance traveled by thief
⇒ speed of policeman x time taken = 1/4 km + speed of thief x time taken
The time taken by the policeman and the thief is the same. Let it be t. Our objective is to find the value of t
Substitute the given set of values in the relation above:
⇒ 9t = 1/4 + 8t
⇒ 9t - 8t = 1/4
⇒ t = 1/4 h
⇒ t = 15 mins
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