Question

The values of 'x' and 'y' when a point lies on the linear equation 2x - 3y = 12
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Answer 1

put first x=0

get y=-4

(0,-4)

then y=0

get x=6

(6,0)

Answer 2

Answer :-

x = 3 and y = -2

Step-by-step explanation :-

Given :-

A point lies on the linear equation 2x - 3y = 12

To find :

Values of x and y ?

Solution :-

➤ Take x = 0 :

⇒ 2(0) - 3y = 12

⇒ -3y = 12

⇒  y = -4

∴ It does not satisfy.

➤ Take x = 1 :

⇒ 2(1) - 3y = 12

⇒ -3y = 10

⇒  y = 10/-3

∴ It does not satisfy.

➤ Take x = 2 :

⇒ 2(2) - 3y = 12

⇒ 4 - 3y = 12

⇒ -3y = 8

⇒ y = -8/3

∴ It does not satisfy.

➤ Take x = 3 :

⇒ 2(3) - 3y = 12

⇒ 6 - 3y = 12

⇒ -3y = 6

⇒ y = -2 and x = 3

∴,

⇛ 2x - 3y = 12

⇛ 2(3) - 3(-2) = 12

⇛ 6 - (-6) = 12

⇛ 12 = 12

⇛ L.H.S = R.H.S

∴ It is satisfied.