A thermally insulated vessel contains an ideal gas of molecular mass M and ratio of specific heats γ . it is moving with speed v and its suddenly brought to rest . Assuming no heat is lost to the surrounding ,its temprature increases by [AIEEE 2011]
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Explanation:- Ad no heat is lost ,
Loss of kinetic energy = gain of internal energy
⟹ 1/2mv² = nCᵥ ∆T
Let the mass of ideal gas is ' m' and given molecular mass 'M 'so mole 'n ' = m/M
as we know that Cᵥ = R/γ-1
⟹ ∴ 1/2mv² = m/M × R ×ΔT /γ-1
⟹ ∆T = Mv²(γ-1)K/2R Answer
Its temprature increases by Mv²(γ-1)k/2R
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